How to Sort a Dictionary by Value in Python

Suppose we have a dictionary that contains unsorted values.

unsorted_dict = {
    "one": 1,
    "zero": 0,
    "three": 3,
    "two": 2
}

We want to sort this dictionary based on these values to get this resulting sorted dictionary.

sorted_dict = {
    "zero": 0,
    "one": 1,
    "two": 2,
    "three": 3
}

We can use the sorted() function to achieve this.

sorted_dict = dict(sorted(unsorted_dict.items(), key=lambda item: item[1]))
print(sorted_dict) # {'zero': 0, 'one': 1, 'two': 2, 'three': 3}

We can sort descending just by adding reverse=True.

sorted_dict = dict(sorted(unsorted_dict.items(), key=lambda item: item[1], reverse=True))
print(sorted_dict) # {'three': 3, 'two': 2, 'one': 1, 'zero': 0}

Finally, we can get the same ascending, sorted result using dictionary comprehension.

sorted_dict = {k: v for k, v in sorted(unsorted_dict.items(), key=lambda item: item[1])}
print(sorted_dict) # {'zero': 0, 'one': 1, 'two': 2, 'three': 3}

How to Sort a Dictionary by Value in Python

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